3f^2+87f+18=0

Solution for 3f^2+87f+18=0 equation:

3f^2+87f+18=0

a = 3; b = 87; c = +18;
Δ = b2-4ac
Δ = 872-4·3·18
Δ = 7353
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$f_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$f_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{7353}=\sqrt{9*817}=\sqrt{9}*\sqrt{817}=3\sqrt{817}$
$f_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(87)-3\sqrt{817}}{2*3}=\frac{-87-3\sqrt{817}}{6}
$
$f_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(87)+3\sqrt{817}}{2*3}=\frac{-87+3\sqrt{817}}{6}
$